Rational Equations Answers
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The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators.The resulting equation is
A
+ 2 – 1 = x – 3B
3x(x + 2) – (x – 2) = x – 3C
(x – 2)(x + 2) – 1 = (x – 3)(x – 2)D
(x – 2)(x + 2) – 3x = (x – 2)(x – 3)2
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The solutions to 15(2a – 2) = 5(a2 – 1) are:
A
a = 1, a = –1B
a = 5, a = –1C
a = 5, a = 13
Which of the solutions are extraneous?
A
6B
1C
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