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Slopes of Parallel and Perpendicular Lines

Question 11 • JHS-Algebra 1A (full year)

Step 4: Write the equation of the line parallel to 3x – y = 7 that passes through point (–5, –3).

Answer
A
y = 3x + 12
B
y = –3x + 12
C
y = –3x – 12
D
y = 3x – 12

Explanation

Rewrite 3x − y = 7 in slope-intercept form: y = 3x − 7, so its slope is 3. A parallel line has the same slope. Using the point (−5, −3), write y = 3x + b; substituting gives −3 = 3(−5) + b, so b = 12. The equation is y = 3x + 12, choice A.

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