Quadratic Functions: Standard Form Answers

Which parabola will have a minimum value vertex?

Domain = {x| }

Range = {y| y ≤ }

Graph this function: f(x) = x^2 −4x − 5 | Steps: Step 1: Identify a and b. | Step 1: | Step 2: Find the vertex using the formula x=−b2ax = \frac {-b}{2a}. x=42(1)x = \frac {4}{2(1)} | Step 2: | Step 3: Plot the vertex. | Step 3: | Step 4: Factor the function to find the x-intercepts. | Step 4: | Step 5: Plot the x-intercepts. | Step 5: | Step 6: Find the y-intercept. | Step 6: | Step 7: Plot the y-intercept. | Step 7: | Step 8: The smooth curve through these points shows the graph of the function. | Step 8: | [(2) =]

Graph this function: f(x) = x^2 −4x − 5 | Steps: Step 1: Identify a and b. | Step 1: | Step 2: Find the vertex using the formula x=−b2ax = \frac {-b}{2a}. x=42(1)x = \frac {4}{2(1)} | Step 2: | Step 3: Plot the vertex. | Step 3: | Step 4: Factor the function to find the x-intercepts. | Step 4: | Step 5: Plot the x-intercepts. | Step 5: | Step 6: Find the y-intercept. | Step 6: | Step 7: Plot the y-intercept. | Step 7: | Step 8: The smooth curve through these points shows the graph of the function. | Step 8: | [-intercepts are:]

Graph this function: f(x) = x^2 −4x − 5 | Steps: Step 1: Identify a and b. | Step 1: | Step 2: Find the vertex using the formula x=−b2ax = \frac {-b}{2a}. x=42(1)x = \frac {4}{2(1)} | Step 2: | Step 3: Plot the vertex. | Step 3: | Step 4: Factor the function to find the x-intercepts. | Step 4: | Step 5: Plot the x-intercepts. | Step 5: | Step 6: Find the y-intercept. | Step 6: | Step 7: Plot the y-intercept. | Step 7: | Step 8: The smooth curve through these points shows the graph of the function. | Step 8: | [(0) =]