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Solving Equations using Properties of Logarithms

Question 2 of 4 • PBCSD_Grade_Forgiveness_1200330_Algebra 2_S2_2024

What are the potential solutions to the equation?

Answer
A
= –4 and x = 2
B
x = –4 and x = –2
C
x = –2 and x = 4
D
= 2 and x = 4
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