Adding and Subtracting Rational Expressions Answers

11 verified answers

The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators.The resulting equation is

+ 2 – 1 = x – 3

3x(x + 2) – (x – 2) = x – 3

(x – 2)(x + 2) – 1 = (x – 3)(x – 2)

(x – 2)(x + 2) – 3x = (x – 2)(x – 3)

x =

Answer:

x = is a solution.

Answer:

x = is an extraneous solution.

Answer:

-2

a = .

Answer:

Question text not available

15(a2 – 1) = 5(2a – 2)

15(2a – 2) = 5(a2 – 1)

15(a2 – 1)(2a – 2) = 5(2a – 2)(a2 – 1)

The solutions to 15(2a – 2) = 5(a2 – 1) are:

a = 1, a = –1

a = 5, a = –1

a = 5, a = 1

The extraneous solution is a = .

Answer:

Rewrite as a proportion.Which of these proportions is equivalent to the original equation?

Option

Which of the solutions are extraneous?

Neither

Solve the original equation by solving the proportion. The solutions are

–6, –1

–6, 1

–1, 6

1, 6

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