Text Structures in Wheels of Change, Part 2

Question 1

Which text features are used in this example? Check all that apply.

Revolt · Accepted Answer

caption; image

Question 2

Factor 20x2 + 25x – 12x – 15 by grouping. 1. Group terms with common factors. 2. Factor the GCF from each group. 3. Write the polynomial as a product of binomials. (20x2 – 12x) + (25x– 15) 4x(5x – 3) + 5(5x – 3) (5x – 3)( x + )

Revolt · Accepted Answer

Part 1: 4; Part 2: 5

Question 3

Use the drop-down menus to complete the statements about factoring 14x2 + 6x – 7x – 3 by grouping. The GCF of the group (14x2 – 7x) is . The GCF of the group (6x – 3) is . The common binomial factor is . The factored expression is .

Revolt · Accepted Answer

7x; Selection 1: 7x; Selection 2: 3; Selection 3: 2x – 1; Selection 4: (7x + 3)(2x – 1)

Question 4

Question 9

Revolt · Accepted Answer

3

Question 5

Question 10

Revolt · Accepted Answer

2x – 1

Question 6

Question 11

Revolt · Accepted Answer

(7x + 3)(2x – 1)

Question 7

Factor the polynomial 3x4 – 2x2 + 15x2 – 10 by grouping.Which product is the factored form of the polynomial?

Revolt · Accepted Answer

(x2 + 5)(3x2 – 2)

Question 8

Which polynomial has (3x + 2) as a binomial factor?

Revolt · Accepted Answer

12x2 + 15x + 8x + 10

Question 9

Which polynomials are prime? Check all that apply.

Revolt · Accepted Answer

15x2 + 10x – 9x + 7; 8x3 + 20x2 + 3x + 12; 11x4 + 4x2 – 6x2 – 16

Question 10

Talia noticed that she does not have a common factor. What should she do?

Revolt · Accepted Answer

Talia needs to factor out a negative from one of the groups so the binomials will be the same.

Text Structures in Wheels of Change, Part 2 Answers

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