Question 1 • (OC27) ALG 2-1200330-S1-Degele-VOL7006P
A perfect cube has a numerical factor that is a cube and variable exponents that are multiples of 3. Since −1,000 = (−10)³, choice A is a perfect cube. Also, 27r²¹ = (3r⁷)³, g³h³⁰ = (gh¹⁰)³, and −1 = (−1)³, so B, D, and E qualify. In 343p, the exponent of p is 1, not a multiple of 3, so C is not a perfect cube.
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