AnswersCR27 ALG 1-1200310-S2-Degele-VOL7006PIntroduction to Quadratic Functions

Introduction to Quadratic Functions Answers

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3

Which equation represents a quadratic function with a leading coefficient of 2 and a constant term of –3?

A
f(x) = 2x3 – 3
B
f(x) = –3x2 – 3x + 2
C
f(x) = –3x3 + 2
D
f(x) = 2x2 + 3x – 3
4

What possible changes can Martha make to correct her homework assignment? Select two options.

A
The first term, 5x3, can be eliminated.
B
The exponent on the first term, 5x3, can be changed to a 2 and then combined with the second term, 2x2.
C
The exponent on the second term, 2x2, can be changed to a 3 and then combined with the first term, 5x3.
D
The constant, –3, can be changed to a variable.
E
The 7x can be eliminated.
5

Which represents a quadratic function?

A
f(x) = 2x3 + 2x2 – 4
B
f(x) = –7x2 – x + 2
C
f(x) = –3x + 2
D
f(x) = 0x2 + 3x – 3
8

When the polynomial is written in standard form, what are the values of the leading coefficient and the constant?5x + 2 – 3x2

A
The leading coefficient is 5, and the constant is 2.
B
The leading coefficient is 2, and the constant is 5.
C
The leading coefficient is –3, and the constant is 2.
D
The leading coefficient is 2, and the constant is –3.
9

Which graph represents a quadratic function with a vertex at (0, 0)?

A
On a coordinate plane, a parabola opens up. It goes through (negative 5, 6), has a vertex of (0, 1), and goes through (5, 6).
Option A
B
On a coordinate plane, a parabola opens up. It goes through (negative 6, 6), has a vertex of (0, negative 1), and goes through (6, 6).
Option B
C
On a coordinate plane, a parabola opens up. It goes through (negative 5, 6), has a vertex of (0, 0), and goes through (5, 6).
Option C
D
On a coordinate plane, a parabola opens up. It goes through (negative 2.5, 6), has a vertex of (3, 0), and goes through (7.5, 4).
Option D

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