Question 3 • Precalculus
The function r(x) = 11/(x − 4)² is not one-to-one across its full domain, so restrict it to one side of x = 4. For the restriction x > 4, solve y = 11/(x − 4)² for x: x − 4 = √(11/y), so r⁻¹(y) = 4 + √(11/y). This matches the choice with x > 4 and the positive square root.
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