The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. Suppose intensity is 8000 units at a distance of 2 miles. What will the intensity be at a distance of 11 miles? Round your answer to the nearest unit.

Because intensity varies inversely with the square of distance, I = k/d². Using 8000 units at 2 miles gives k = 8000 × 2² = 32,000; at 11 miles, the intensity is 32,000 ÷ 11² = 32,000 ÷ 121 ≈ 264.46, which rounds to 264 units. The correct choice is 264 units.

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