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To answer this question, you used weight to change the ✔ pressuresolubilitytemperature of the gas and measured the
resulting changes to the gas’s pressure.✔ volume.weight.
The amount of gas (in terms of moles, mass, and molecules) decreased✔ was constantfluctuated randomlyincreased
Based on Charles’sAvogadro’s✔ Boyle’sHess’s law, pressure and volume were expected to be inversely proportional.
Did the data support the hypothesis (above)? ✔ yessomewhatno
Justify your answer.
As weight was added to the syringe, the pressure on the trapped air increased and its volume decreased. Therefore, the data supported the hypothesis.
Sample Justification: As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.
Sample Justification: As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.
Look back at your data and your regression equation. (Sample data is shown to the right, with x = pressure and y = volume.) Check all statements that are true.

A student doing this experiment obtained the data shown in the table above. The value of the constant, k, for this data is 0.0425.750.0✔ 51.5
Since P • V was the same for all pressures, this student’s data was inaccuraterandom✔ accurate
Suppose that the student took one more volume reading of 24.2 mL but forgot to measure the pressure. Compute the pressure expected for that volume. 1.221.47✔ 2.134.26 kg/cm²
Check all actions that change the constant k.
Check all reasons why a syringe was a good choice of tool in this experiment.
Check all reasons why a book was used.
You are trying to make balloon sculptures. You twist the balloons gently, but they keep popping. Besides trimming your nails, how could you you prevent that? Why will your strategy work?
Inflate the balloons less and leave some uninflated space. That gives the air room to move when you twist the balloon, so the pressure rises less and the balloon is less likely to pop.
Did you suggest filling the balloons with less air, thereby decreasing the pressure? yesnosort of
Air pressure is lower at high altitudes. An airplane cabin can adjust, but as the plane rises, passengers can experience temporary pain in their ears. Check all facts below that explain why.
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