Lab: Charles's Law

Question 1

Question 1

Revolt · Accepted Answer

of the gas between 0 and 100°C: temperature; of the gas.: volume

Question 2

To test this hypothesis, you changed the pressuresolubility✔ temperature of the gas between 0 and 100°C

Revolt · Accepted Answer

✔ temperature; of the gas between 0 and 100°C: temperature; of the gas.: volume

Question 3

(273 and 373 K) and calculated the resulting pressure✔ volumetemperature of the gas.

Revolt · Accepted Answer

✔ volume

Question 4

Question 4

Revolt · Accepted Answer

and the dependent variable was: temperature; .: volume

Question 5

Therefore the independent variable was pressuresolubility✔ temperature and the dependent variable was

Revolt · Accepted Answer

✔ temperature; and the dependent variable was: temperature; .: volume

Question 6

pressure✔ volumetemperature.

Revolt · Accepted Answer

✔ volume

Question 7

A beaker half full of liquid. Which glass container was used in the experiment to heat the water bath?

Revolt · Accepted Answer

beaker

Question 8

Which is the best reason for choosing the beaker for heating the solution?

Revolt · Accepted Answer

The beaker's wide mouth allows the thermometer to rest against the side.

Lab: Charles's Law Answers