Lesson 10.9: Equation of a Circle Answers
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In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation of a circle, x2 + y2 = r2.
A
(h + x)2 + (k + y)2 = r2B
(x – h)2 + (y – k)2 = r2C
(k + x)2 + (h + y)2 = r2D
(x – k)2 + (y – h)2 = r222
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What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0?
A
(–12, –2)B
(–6, –1)C
(6, 1)D
(12, 2)23
Distance formula:
A
Yes, the distance from (–2, 4) to (1, ) is 4 units.
B
Yes, the distance from (–2, 0) to (1, ) is 4 units.C
No, the distance from (–2, 0) to (1, ) is not 4 units.D
No, the distance from (–2, 4) to (1, ) is not 4 units.24
On a coordinate plane, a circle has a center at (1, negative 2) and a radius of 4 units.
A
(x – 1)2 + (y + 1)2 = 16B
(x – 1)2 + (y + 1)2 = 4C
(x + 1)2 + (y –1)2 = 4D
(x + 1)2 + (y – 1)2 = 1625
What is the center of a circle represented by the equation (x+9)2+(y−6)2=102?
A
(−9,6)B
(−6,9)C
(6,−9)D
(9,−6)Did you find these answers helpful?
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