Question 18 • (OC27) MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006P
The price increases by $80 when the number of invitations increases by 40, so the rate is $2 per invitation. Using the 80-invitation price, the fixed portion is $210 − (80 × $2) = $50; for 60 invitations, the price is $50 + (60 × $2) = $170. The correct choice is $170.00.
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