5
AssignmentMultiple Choice

Lesson 4.1: Addition and Subtraction of Polynomials

Question 5 • TX-Algebra II A

Find each difference.(–6s2 + 12s – 8) – (3s2 + 8s – 6) =

Answer
A
–9s2 + 4s – 14
B
–9s2 + 4s – 2
C
–9s2 + 20s – 14
D
–9s2 + 20s – 2

Explanation

Subtract the second polynomial by changing the sign of each of its terms: (–6s² + 12s – 8) – 3s² – 8s + 6. Combine like terms: –6s² – 3s² = –9s², 12s – 8s = 4s, and –8 + 6 = –2. The result is –9s² + 4s – 2, choice B.

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