AnswersFL-1200330-Algebra 2 Sem 1 - FlexLiteral Equations

Literal Equations Answers

10 verified answers
1
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When is solved for c, one equation is Which of the following is an equivalent equation to find c?

Question illustration
A
c = 10 b minus 10 minus 5
Option A
B
c = (10 b minus 10 minus 5) squared
Option B
C
c = StartFraction (10 b minus 2) squared Over 25 EndFraction
Option C
D
c = StartFraction (10b minus 10) squared Over 25 EndFraction
Option D
2
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Remmi wrote the equation of the line He solved for x and got Which of the following is an equivalent equation for x?

Question illustration
A
x = y minus eleven-thirds
Option A
B
x = y + seven-thirds
Option B
C
x = 3 (y minus two-thirds)
Option C
D
x = 3 (y + two-thirds)
Option D
3

The equation is the slope-intercept form of the equation of a line. What is the equation solved for b?

Question illustration
A
y minus m = b
Option A
B
y minus m x = b
Option B
C
StartFraction y Over m x EndFraction = b
Option C
D
StartFraction y Over m EndFraction minus x = b
Option D
4

The formula for the area of a regular polygon is . What is the equation solved for a?

Question illustration
A
a = 2 uppercase A
Option A
B
a = 2 uppercase A minus p
Option B
C
a = StartFraction 2 p Over uppercase A EndFraction
Option C
D
a = StartFraction 2 uppercase A Over p EndFraction
Option D
5

The formula gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Question illustration
A
a Subscript n Baseline = StartFraction 2 uppercase S minus a Subscript 1 Baseline n Over n EndFraction
Option A
B
a Subscript n Baseline = StartFraction 2 uppercase S + a Subscript 1 Baseline n Over n EndFraction
Option B
C
a Subscript n Baseline = 2 uppercase S + a Subscript 1 Baseline n + n
Option C
D
a Subscript n Baseline = 2 uppercase S minus a Subscript 1 Baseline n + n
Option D
6

Paolo wrote the following equation for the perimeter of a rectangle. Which equation is equivalent to the equation Paolo wrote?

Question illustration
A
w = uppercase P minus 2 l
Option A
B
2 = uppercase P minus l
Option B
C
w = StartFraction uppercase P minus 2 l Over 2 EndFraction
Option C
D
w = StartFraction uppercase P + 2 l Over 2 EndFraction
Option D
7

A student solves the equation using the steps in the table. Original equationCross multiplicationDistributive propertySubtraction property of equality5 = xWhich method of solving for the variable could be used instead of cross multiplication?

Question illustration
A
distributing x + 3 and then 3x + 5 to both sides of the equation
B
distributing x – 3 and then 3x – 5 to both sides of the equation
C
using the multiplication property of equality to multiply both sides of the equation by 10
D
using the multiplication property of equality to multiply both sides of the equation by
Option D
8

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solved for m?

A
m = StartFraction s minus c Over c EndFraction
Option A
B
m = StartFraction s + c Over c EndFraction
Option B
C
s minus c = m
Option C
D
s + c = m
Option D
9

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

Question illustration
A
uppercase V squared minus v squared minus 2 x = a
Option A
B
uppercase V squared minus v squared + 2 s = a
Option B
C
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Option C
D
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Option D
10

The formula for the nth term of an arithmetic sequence can be found using the formula . Which of the following is equivalent to this equation?

Question illustration
A
n = a Subscript n Baseline + a Subscript 1
Option A
B
n = StartFraction a Subscript n Baseline + a Subscript 1 Baseline minus 3 Over d EndFraction
Option B
C
n = a Subscript n Baseline minus a Subscript 1
Option C
D
n = a Subscript n Baseline minus a Subscript 1 Baseline + d Over d EndFraction
Option D

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