AnswersFL-1200700-Mathematics for College Algebra MISInequalities

Literal Equations Answers

10 verified answers
1
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The formula for the area of a regular polygon is . What is the equation solved for a?

Question illustration
A
a = 2 uppercase A
Option A
B
a = 2 uppercase A minus p
Option B
C
a = StartFraction 2 p Over uppercase A EndFraction
Option C
D
a = StartFraction 2 uppercase A Over p EndFraction
Option D
2
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A student solves the equation for v. Start with the original equation.Use the division property of equality.Use the multiplication property of equality.Use the square root property of equality.Simplify.Which statement explains how to correct the error that was made?

Question illustration
A
The subtraction property of equality should have been applied to move m to the other side of the equation.
B
The multiplication property of equality should have been applied in the last step.
C
The division property of equality should have been used to divide by k instead of m.
D
The square root property should have been applied to both complete sides of the equation instead of to select variables.
3

Given the equation , which equation is solved for t?

Question illustration
A
t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)
Option A
B
t = p minus s Subscript 1 Baseline minus s Subscript 2
Option B
C
t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
Option C
D
t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction
Option D
4

Which equation is equivalent to

Question illustration
A
s = t minus 2
Option A
B
s = StartFraction 4 Over t + 2 EndFraction
Option B
C
s = StartFraction t + 2 Over 4 EndFraction
Option C
D
s = t + 6
Option D
5

The formula for the nth term of an arithmetic sequence can be found using the formula . Which of the following is equivalent to this equation?

Question illustration
A
n = a Subscript n Baseline + a Subscript 1
Option A
B
n = StartFraction a Subscript n Baseline + a Subscript 1 Baseline minus 3 Over d EndFraction
Option B
C
n = a Subscript n Baseline minus a Subscript 1
Option C
D
n = a Subscript n Baseline minus a Subscript 1 Baseline + d Over d EndFraction
Option D
6

Which of the following equations is equivalent to ?

Question illustration
A
h = uppercase S minus pi r squared
Option A
B
h = StartFraction uppercase S Over pi r squared EndFraction
Option B
C
h = StartFraction pi r squared Over uppercase S EndFraction
Option C
D
h = uppercase S + pi r squared
Option D
7

The formula gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Question illustration
A
a Subscript n Baseline = StartFraction 2 uppercase S minus a Subscript 1 Baseline n Over n EndFraction
Option A
B
a Subscript n Baseline = StartFraction 2 uppercase S + a Subscript 1 Baseline n Over n EndFraction
Option B
C
a Subscript n Baseline = 2 uppercase S + a Subscript 1 Baseline n + n
Option C
D
a Subscript n Baseline = 2 uppercase S minus a Subscript 1 Baseline n + n
Option D
8

Gavin wrote the equation to represent p, the profit he makes from s sales in his lawn-mowing business. Which equation is solved for s?

Question illustration
A
s = StartFraction p minus 100 Over 3 EndFraction
Option A
B
s = StartFraction 4 p minus 300 Over 3 EndFraction
Option B
C
s = StartFraction 4 p Over 300 EndFraction
Option C
D
s = StartFraction 400 p Over 3 EndFraction
Option D
9

The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

Question illustration
A
360 uppercase A + pi r squared
Option A
B
360 uppercase A minus pi r squared
Option B
C
StartFraction 360 + uppercase A Over pi r squared EndFraction
Option C
D
StartFraction 360 uppercase A Over pi r squared EndFraction
Option D
10

When is solved for c, one equation is Which of the following is an equivalent equation to find c?

Question illustration
A
c = 10 b minus 10 minus 5
Option A
B
c = (10 b minus 10 minus 5) squared
Option B
C
c = StartFraction (10 b minus 2) squared Over 25 EndFraction
Option C
D
c = StartFraction (10b minus 10) squared Over 25 EndFraction
Option D

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