AnswersHCISD Algebra II A-CRRelations and Functions

Literal Equations Answers

0 verified answers1 views
1
Free Preview

The formula for the nth term of an arithmetic sequence can be found using the formula . Which of the following is equivalent to this equation?

Question illustration
A
n = a Subscript n Baseline + a Subscript 1
Option A
B
n = StartFraction a Subscript n Baseline + a Subscript 1 Baseline minus 3 Over d EndFraction
Option B
C
n = a Subscript n Baseline minus a Subscript 1
Option C
D
n = a Subscript n Baseline minus a Subscript 1 Baseline + d Over d EndFraction
Option D
2
Free Preview

Question is locked

Question illustration
Answer not available
3

Question is locked

Question illustration
Answer not available
4

The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

Question illustration
A
360 uppercase A + pi r squared
Option A
B
360 uppercase A minus pi r squared
Option B
C
StartFraction 360 + uppercase A Over pi r squared EndFraction
Option C
D
StartFraction 360 uppercase A Over pi r squared EndFraction
Option D
5

Question is locked

Question illustration
Answer not available
6

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solved for m?

A
m = StartFraction s minus c Over c EndFraction
Option A
B
m = StartFraction s + c Over c EndFraction
Option B
C
s minus c = m
Option C
D
s + c = m
Option D
7

Question is locked

Question illustration
Answer not available
8

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

Question illustration
A
uppercase V squared minus v squared minus 2 x = a
Option A
B
uppercase V squared minus v squared + 2 s = a
Option B
C
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Option C
D
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Option D
9

If , which equation is solved for t?

Question illustration
A
I – pr = t
B
StartFraction uppercase I minus p Over r EndFraction = t
Option B
C
StartFraction uppercase I Over p r EndFraction = t
Option C
D
I + pr = t
10

Which of the following equations is equivalent to ?

Question illustration
A
h = uppercase S minus pi r squared
Option A
B
h = StartFraction uppercase S Over pi r squared EndFraction
Option B
C
h = StartFraction pi r squared Over uppercase S EndFraction
Option C
D
h = uppercase S + pi r squared
Option D
11

A student solves the equation using the steps in the table. Original equationCross multiplicationDistributive propertySubtraction property of equality5 = xWhich method of solving for the variable could be used instead of cross multiplication?

Question illustration
A
distributing x + 3 and then 3x + 5 to both sides of the equation
B
distributing x – 3 and then 3x – 5 to both sides of the equation
C
using the multiplication property of equality to multiply both sides of the equation by 10
D
using the multiplication property of equality to multiply both sides of the equation by
Option D
12

Paolo wrote the following equation for the perimeter of a rectangle. Which equation is equivalent to the equation Paolo wrote?

Question illustration
A
w = uppercase P minus 2 l
Option A
B
2 = uppercase P minus l
Option B
C
w = StartFraction uppercase P minus 2 l Over 2 EndFraction
Option C
D
w = StartFraction uppercase P + 2 l Over 2 EndFraction
Option D
13

A student solves the equation for v. Start with the original equation.Use the division property of equality.Use the multiplication property of equality.Use the square root property of equality.Simplify.Which statement explains how to correct the error that was made?

Question illustration
A
The subtraction property of equality should have been applied to move m to the other side of the equation.
B
The multiplication property of equality should have been applied in the last step.
C
The division property of equality should have been used to divide by k instead of m.
D
The square root property should have been applied to both complete sides of the equation instead of to select variables.
14

The formula for the area of a regular polygon is . What is the equation solved for a?

Question illustration
A
a = 2 uppercase A
Option A
B
a = 2 uppercase A minus p
Option B
C
a = StartFraction 2 p Over uppercase A EndFraction
Option C
D
a = StartFraction 2 uppercase A Over p EndFraction
Option D

Did you find these answers helpful?

More from this Course

Quiz
15 verified answers

Relations and Functions

Quiz
15 verified answers

Function Operations

Quiz
10 verified answers

Relations and Functions