Answers CA-Common Core Algebra II A-CRLinear Functions

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The formula for the area of a regular polygon is . What is the equation solved for a?

a = 2 uppercase A

a = 2 uppercase A minus p

a = StartFraction 2 p Over uppercase A EndFraction

a = StartFraction 2 uppercase A Over p EndFraction

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The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

360 uppercase A + pi r squared

360 uppercase A minus pi r squared

StartFraction 360 + uppercase A Over pi r squared EndFraction

StartFraction 360 uppercase A Over pi r squared EndFraction

Which of the following equations is equivalent to ?

h = uppercase S minus pi r squared

h = StartFraction uppercase S Over pi r squared EndFraction

h = StartFraction pi r squared Over uppercase S EndFraction

h = uppercase S + pi r squared

If , which equation is solved for t?

I – pr = t

StartFraction uppercase I minus p Over r EndFraction = t

StartFraction uppercase I Over p r EndFraction = t

I + pr = t

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

uppercase V squared minus v squared minus 2 x = a

uppercase V squared minus v squared + 2 s = a

StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a

StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solved for m?

m = StartFraction s minus c Over c EndFraction

m = StartFraction s + c Over c EndFraction

s minus c = m

s + c = m

Given the equation , which equation is solved for t?

t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)

t = p minus s Subscript 1 Baseline minus s Subscript 2

t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction

A student solves the equation using the steps in the table. Original equationCross multiplicationDistributive propertySubtraction property of equality5 = xWhich method of solving for the variable could be used instead of cross multiplication?