What is the true solution to the given equation? 2 log sub 3 6 x minus log sub 3 of 4 x is equal to 2 log sub 3 open paren x plus 2 close paren
A
x is equal to negative 2 and x is equal to 1B
x is equal to 2 and x is equal to 4C
x is equal to negative 2 and x is equal to 2D
x is equal to 1 and x is equal to 4