Question 5 • Mathematics III
Let the number be x. Translate the statement into 5(x + 27) ≥ 6(x + 26), which simplifies to 5x + 135 ≥ 6x + 156. Subtracting 5x and 156 gives −21 ≥ x, or x ≤ −21. The solution set is (−∞, −21], choice D.
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