AnswersMO-Algebra II AMixed Degree Systems

Mixed Degree Systems Answers

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Question text not available

Answers:
.:parabola
.:line
2
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What is the maximum number of solutions each of the following systems could have?Two distinct concentric circles: ✔ zeroonetwothreefourinfinitely many

A
✔ zero
B
one
C
two
D
three
E
four
F
infinitely many
3

A line and a circle: zeroone✔ twothreefourinfinitely many

A
zero
B
one
C
✔ two
D
three
E
four
F
infinitely many
4

A parabola and a circle:zeroonetwothree✔ fourinfinitely many

A
zero
B
one
C
two
D
three
E
✔ four
F
infinitely many
5

Two distinct parabolas: zeroone✔ twothreeX fourinfinitely many

A
zero
B
one
C
✔ two
D
three
E
X four
F
infinitely many
6

Which of the following graphs represents the solution(s) of the following system? x2 – y = –2 4y – 8 = x

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
7

Which of the following graphs represents the solution(s) of the following system? x2 + y = 7 x2 + y2 = 49

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
8

Consider the following system of equations:10 + y = 5x + x25x + y = 1The first equation is an equation of a line✔ parabolacircle.

Answers:
.:parabola
.:line
9

The second equation is an equation of a ✔ lineparabolacircle.

A
✔ line
B
parabola
C
circle
10

How many possible numbers of solutions are there to the system of equations?

A
0
B
1
C
2
D
3
E
4
F
infinite
11

Question text not available

Answers:
Blank 1:1
Blank 2:-11
Blank 3:56
12

Question text not available

Answer:

-11

13

Question text not available

Answer:

56

14

Consider the following system of equations:How many solutions does the system have?

Question illustration
A
zero
B
one
C
two
D
three
E
four
F
infinitely many
15

Choose the solution(s) of the following system of equations: x2 + y2 = 6 x2 – y = 6

A
no solution
B
Option
Option B
C
Option
Option C
D
Option
Option D
E
infinitely many solutions
F
Option
Option F
G
Option
Option G
H
Option
Option H
16

The balls meet at a height of ft.

Answer:

40.5

17

Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

Answer:

Set the height equations equal and solve for the time: −16t² + 56t = −16t² + 156t − 248, so t = 2.48 seconds. Substitute 2.48 into either equation to find the height, which is 40.5 feet to the nearest tenth.

18

Which of these steps did you include in your solution? Check all of the boxes that apply.

A
Use substitution to write the equation–16t2 + 56t = –16t2 + 156t – 248.
B
Simplify and solve for t, which is 2.48 s.
C
Substitute 2.48 for t into either equation to get h = 40.5 ft.

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