The table below shows the composition of three mixtures of nuts. Composition of Nut Mixtures Mixture AMixture BMixture CPecans0.600.500.75Almonds0.300.450.15Walnuts0.100.050.10Mr. Murray wants to create 100 ounces of a mixture that is 62% pecans, 30% almonds, and 8% walnuts. How will the amount of Mixture A compare to the amounts of Mixtures B and C that Mr. Murray uses?

Let the amounts of Mixtures A, B, and C be x, y, and z ounces. Using the almond percentages and the 100-ounce total gives x + 2y = 100; using the pecan percentages gives 3x + 5y = 260. Solving yields x = 20, y = 40, and z = 40, so Mixtures B and C total 80 ounces. Thus, he uses one-quarter as much Mixture A as Mixtures B and C combined.

AI-written and checked against the verified answer.