Question 17 • Algebra II - MA3111 A-IC

Answer:
At $7.50 per soccer ball, the store earns $232.50 in daily profit. It needs another $400 − $232.50 = $167.50 from footballs. Set the football profit equation equal to $167.50 and solve 167.50 = −4x² + 80x − 150. The solutions are approximately $5.46 and $14.54 per football.