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AssignmentLong Text

Modeling with Quadratic Equations

Question 17 • Algebra II - MA3111 A-IC

Soccer balls go on sale for $7.50 each. The store also sells footballs and the manager wants to earn a daily profit of $400 from both items. The equation models the store’s daily profit, y, for selling footballs at x dollars. Explain how to find the price per football needed to meet the goal.

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Answer

Answer:

At $7.50 per soccer ball, the store earns $232.50 in daily profit. It needs another $400 − $232.50 = $167.50 from footballs. Set the football profit equation equal to $167.50 and solve 167.50 = −4x² + 80x − 150. The solutions are approximately $5.46 and $14.54 per football.

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