AnswersFL-1200330-Algebra 2 CRModeling with Quadratic Equations

Modeling with Quadratic Equations Answers

33 verified answers4 views
21
Free Preview

The quadratic function y = –10x2 + 160x – 430 models a store’s daily profit (y) for selling a T-shirt priced at x dollars. What equation do you need to solve to find the selling price or prices that would generate $50 in daily profit? What method would you use to solve the equation? Justify your choice.

Answer:

To find the selling prices that generate a $50 profit, replace y with 50 in the equation: 50 = –10x² + 160x – 430. Next, rewrite the equation in standard form by subtracting 50 from both sides to get 0 = –10x² + 160x – 480. Factoring is the best method because the entire equation can be divided by –10 to get 0 = x² – 16x + 48, which easily factors into (x – 4)(x – 12) = 0. This results in selling prices of $4 or $12.

22
Free Preview

Compare your response with the sample response included here. Did your explanation

A
say to replace y with 50?
B
say that the equation should be in standard form?
C
include factoring as the solution method?
23

Question text not available

Answers:
-coordinate of the vertex of the function:D
-coordinate of the vertex of the function:B
an:C
a:A
30

A sporting goods store uses quadratic equations to monitor the daily cost and profit for various items it sells. The store’s daily profit, y, when soccer balls are sold at x dollars each, is modeled by . Why is there an interval over which the graph decreases?

Question illustration
A
If the store sells more soccer balls, they can decrease the price.
B
If the soccer balls are returned for a refund, the store will lose money.
C
If the soccer balls are too expensive, fewer will be sold, reducing profit.

Did you find these answers helpful?