AnswersAlgebra IModeling with Quadratic Functions

Modeling with Quadratic Functions — Quiz Answers

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4

The zeros of a parabola are negative 4 and 2 , and 6 comma 10 is a point on the graph. Which equation can be solved to determine the value of A in the equation of the parabola?

A
10 is equal to A open paren 6 minus 4 close paren open paren 6 plus 2 close paren
B
10 is equal to A open paren 6 plus 4 close paren open paren 6 minus 2 close paren
C
6 is equal to A open paren 10 minus 4 close paren open paren 10 plus 2 close paren
D
6 is equal to A open paren 10 plus 4 close paren open paren 10 minus 2 close paren
6

The image of a parabolic lens is projected onto a graph. The image crosses the x -axis at negative 2 and 3 The point negative 1 comma 2 is also on the parabola. Which equation can be used to model the image of the lens?

A
y is equal to negative 1 fifth open paren x minus 2 close paren open paren x plus 3 close paren
B
y is equal to negative 1 third open paren x minus 2 close paren open paren x plus 3 close paren
C
y is equal to 1 fourth open paren x plus 2 close paren open paren x minus 3 close paren
D
y is equal to negative 1 half open paren x plus 2 close paren open paren x minus 3 close paren
8

The minimum of a parabola is located at negative 1 comma negative 3 The point 0 comma 1 is also on the graph. Which equation can be solved to determine the a value in the function representing the parabola?

A
0 is equal to A times open paren 1 minus 1 close paren squared plus 3
B
1 is equal to A times open paren 0 minus 1 close paren squared plus 3
C
1 is equal to A times open paren 0 plus 1 close paren squared minus 3
D
0 is equal to A times open paren 1 plus 1 close paren squared minus 3

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