Module 4/ Topic 2 Test Answers

15 verified answers1 views
1
Free Preview

Which expression is equivalent to ?

Question illustration
A
StartFraction x Superscript one-half baseline Over y z squared EndFraction
Option A
B
StartFraction x Superscript one-half baseline Over y Superscript one-fourth Baseline z squared EndFraction
Option B
C
StartFraction y Superscript one-half Baseline Over x z squared EndFraction
Option C
D
StartFraction x z squared Over y Superscript one-half EndFraction
Option D
3

What is the solution of ?

Question illustration
A
x = –10
B
x = 3
C
x = –10 or x = 3
D
no solution
4

Which could be the function graphed below?

Question illustration
A
f (x) = StartRoot x minus 5 EndRoot + 1
Option A
B
f (x) = StartRoot x minus 2 EndRoot
Option B
C
f (x) = StartRoot x EndRoot
Option C
D
f (x ) = StartRoot x + 4 EndRoot
Option D
5

Which function is the inverse of ?

Question illustration
A
f Superscript negative 1 Baseline (x) = negative one-fifth x + four-fifths
Option A
B
mc014-3.jpg
Option B
C
mc014-4.jpg
Option C
D
mc014-5.jpg
Option D
6

If x is a positive integer, which expression is equivalent to ? Assume .

Question illustration
A
RootIndex 20 StartRoot x Superscript 7 EndRoot
Option A
B
x (RootIndex 20 StartRoot x cubed EndRoot)
Option B
C
StartFraction RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot Over x squared EndFraction
Option C
D
x cubed (RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot)
Option D
7

Which of the following is the graph of ?

Question illustration
A
On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = negative 1.
Option A
B
On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.
Option B
C
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = 1.
Option C
D
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = negative 1.
Option D
8

What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction RootIndex 5 StartRoot 10 x EndRoot Over 3 x EndFraction
Option A
B
StartFraction RootIndex 5 StartRoot 30 EndRoot Over 3 x EndFraction
Option B
C
StartFraction RootIndex 5 StartRoot 120 x cubed EndRoot Over 3 x EndFraction
Option C
D
StartFraction RootIndex 5 StartRoot 810 x cubed EndRoot Over 3 x EndFraction
Option D
9

Which equation is the inverse of y = 7x2 – 10?

A
y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction
Option A
B
y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot
Option B
C
x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot
Option C
D
y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction
Option D
10

If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot 4 x EndRoot greater-than-or-equal-to 0
Option A
B
4 x + 9 greater-than-or-equal-to 0
Option B
C
4 x greater-than-or-equal-to 0
Option C
D
StartRoot 4 x + 9 EndRoot + 2 greater-than-or-equal-to 0
Option D
11

What is the following quotient?

Question illustration
A
2 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
Option A
B
2 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
Option B
C
3 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
Option C
D
3 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
Option D
13

Which function has a domain of and a range of ?

Question illustration
A
y = StartRoot x minus 5 EndRoot + 3
Option A
B
y = StartRoot x + 5 EndRoot minus 3
Option B
C
y = negative StartRoot x minus 5 EndRoot + 3
Option C
D
y = negative StartRoot x + 5 EndRoot minus 3
Option D
14

What is the following simplified product? Assume

Question illustration
A
3 x StartRoot 6 x EndRoot + x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared + 8 x Superscript 5 Baseline StartRoot 10 x EndRoot
Option A
B
3 x StartRoot 6 x EndRoot + x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 EndRoot + 8 x Superscript 5 Baseline StartRoot 10 EndRoot
Option B
C
3 x StartRoot 6 x EndRoot minus x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 EndRoot minus 8 x Superscript 5 Baseline StartRoot 10 EndRoot
Option C
D
3 x StartRoot 6 x EndRoot minus x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 x EndRoot minus 8 x Superscript 5 Baseline StartRoot 10 x EndRoot
Option D

Did you find these answers helpful?