Question 18 • FL-2003310-Physical Science CR
The pitcher and ball start at rest, so their total momentum is zero. After the throw, conservation of momentum gives (0.15 kg)(35 m/s) + (50 kg)v = 0, so v = −5.25/50 = −0.105 m/s. Rounded to the nearest tenth, the pitcher’s velocity is −0.1 m/s, choice A.
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