Question 2 • Sem 2 - Algebra 2 with Probability - Nkwati - Content
With a = 1, the function is y = xⁿ. Since n is even, both 1ⁿ and (−1)ⁿ equal 1, and 0ⁿ equals 0. So the graph passes through (−1, 1), (0, 0), and (1, 1), as stated in choice C.
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