What is 6[cos(70°) + i sin(70°)] ÷ 2[cos(5°) + i sin(5°)]?

To divide complex numbers in trigonometric form, divide their magnitudes and subtract their angles. The magnitude is 6 ÷ 2 = 3, and the angle is 70° − 5° = 65°. Therefore, the quotient is 3[cos(65°) + i sin(65°)], which is choice C.

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