What is the following product? cube root of 4 times square root of 3

Rewrite both radicals with an index of 6: ∛4 = ⁶√(4²) and √3 = ⁶√(3³). Multiplying them gives ⁶√(16 × 27) = ⁶√432, so the product is the sixth root of 432.

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