Question 86 • Algebra II
An x-intercept occurs where y = 0, so solve mx² − 5x − 2 = 0. For a quadratic to have no real solutions, its discriminant must be negative: (−5)² − 4(m)(−2) = 25 + 8m < 0, which gives m < −25/8. Therefore, the correct choice is “m is less than negative 25 eighths.”
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