A negative 0 point 0 6 cap c charge is placed is in a uniform electric field with a strength of 200 cap n over cap c What is the magnitude and direction of the force on the charge?

The force magnitude is given by F = |q|E. Using |q| = 0.06 C and E = 200 N/C gives F = 0.06 × 200 = 12 N. Because the charge is negative, the force points opposite the electric field, so the correct choice is 12 N in the opposite direction of the field.

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