AnswersChemistryN/A — ExamQuestion 12
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N/A — Exam

Question 12 • Chemistry

A gas in a rigid container at 25 times degree C has a pressure of 0 point 9 6 atm. A change in temperature causes the pressure to increase to 1 point 2 5 atm. What is the new temperature of the gas? Use the fraction with numerator cap p sub 1 and denominator cap t sub 1 is equal to the fraction with numerator cap p sub 2 and denominator cap t sub 2

Answer
A
negative 44 point 2 times degree C
B
115 times degree C
C
32 point 6 times degree C
D
338 times degree C

Explanation

At constant volume, pressure is proportional to absolute temperature, so use kelvins in P₁/T₁ = P₂/T₂. Convert 25°C to 298 K, then T₂ = 298 × (1.25/0.96) ≈ 388 K. Converting back gives 388 − 273 ≈ 115°C, so the new temperature is 115°C.

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