Question 38 • Algebra II
Multiply the first equation by 7: 5x² + 6y² = 50 becomes 35x² + 42y² = 350. Multiply the second equation by −5: 7x² + 2y² = 10 becomes −35x² − 10y² = −50. Multiplying an equation by a nonzero number preserves its solutions, so choice B is equivalent to the original system.
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