The scores of an eighth-grade math test have a normal distribution with a mean mu is equal to 83 and a standard deviation sigma is equal to 5 If Din’s test score was 92 , which expression would she write to find the z -score of her test score?
Answer
A
z is equal to the fraction with numerator 83 minus 92 and denominator 5
B
z is equal to the fraction with numerator 5 minus 83 and denominator 92
C
z is equal to the fraction with numerator 92 minus 83 and denominator 83
D
z is equal to the fraction with numerator 92 minus 83 and denominator 5