The heights of the trees in a forest are normally distributed, with a mean of 25 meters and a standard deviation of 6 meters. What is the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters? Use the portion of the standard normal table given to help answer the question. z Probability 0 point 0 0 0 point 5 0 0 0 0 point 5 0 0 point 6 9 1 5 1 point 0 0 0 point 8 4 1 3 2 point 0 0 0 point 9 7 7 2 3 point 0 0 0 point 9 9 8 7
Convert the height to a z-score: (37 − 25) ÷ 6 = 2. The table gives a probability of 0.9772 for a tree at or below 37 meters, so the probability of a height at least 37 meters is 1 − 0.9772 = 0.0228, or 2.28%. This rounds to 2.3 percent, choice A.
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