A deposit of $1,500 has an annual interest rate of 4% and is compounded monthly. How much will the investment be worth at the end of 3.75 years? A=P⁢(1+(r)/(n))^n⁢t

Use the compound-interest formula with P = $1,500, r = 0.04, n = 12, and t = 3.75. There are 12 × 3.75 = 45 monthly compounding periods, so A = 1,500(1 + 0.04/12)^45 ≈ $1,742.32. The investment will be worth about $1,742.32, which is choice B.

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