Study the work shown below and compare the results to the product of –2i(6 – 7i).(0 – 2i)(6 – 7i)= (0)(6) + (0)(–7i) + (–2i)(6) + (–2i)(–7i)= 0 + 0 –12i + 14i2= –12i – 14= –14 –12iThe products are ⇒ equal.