Mr. Lee asks a student to solve the following system of linear equations. negative 28 is equal to negative 40 q minus 14 p 10 q plus 4 is equal to 2 p Which ordered pair open paren p comma q close paren is the solution to the system?

From 10q + 4 = 2p, divide by 2 to get p = 5q + 2. Substitute this into −28 = −40q − 14p: −28 = −40q − 14(5q + 2) = −110q − 28, so q = 0. Then p = 5(0) + 2 = 2, giving the ordered pair (2, 0), choice A.

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