Question 21 • Mathematics III
For y = −2^x − 1, first calculate the values: at x = 0, y = −1 − 1 = −2; at x = 1, y = −2 − 1 = −3; and at x = 2, y = −4 − 1 = −5. As x becomes very negative, 2^x approaches 0, so the graph approaches y = −1. Choice C has these points and this horizontal asymptote.
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