The ideal gas law states that the volume, v , of a gas in liters varies directly with the amount of the gas in moles, n , and the absolute temperature, cap t , in kelvins and varies inversely with the pressure, cap p , in atmospheres. Two moles of a gas have a volume of 35 point 4 2 4 L at 270 kelvins when cap p is equal to 1 point 2 5 atmospheres. What is the volume of 3 moles of a gas at 280 kelvins when cap p is equal to 1 point 5 atmospheres?
Since volume varies directly with moles and temperature and inversely with pressure, use V₂ = V₁(n₂/n₁)(T₂/T₁)(P₁/P₂). Substituting the values gives V₂ = 35.424 × (3/2) × (280/270) × (1.25/1.5) = 45.92 L. The correct choice is 45.92 L.
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