A certain board game used a spinner divided into 12 equal regions showing the numbers 1 – 12 If the spinner is used four times, what is the probability that the result is a number 8 or larger at least once?

Numbers 8 through 12 give 5 successful regions, so the chance of not getting 8 or larger on one spin is 7/12. The chance of avoiding those numbers on all four spins is (7/12)^4. Therefore, the probability of getting 8 or larger at least once is 1 − (7/12)^4 ≈ 0.8842, which matches choice D.

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