The daily high temperatures in a vacation resort city are approximately Normal, with a mean temperature of 75 degrees Fahrenheit and a standard deviation of 6 degrees. If a weather forecast predicts the high temperature will be at most 68 degrees, the city provides fewer lifeguards for the city beaches. On what percentage of days will fewer lifeguards be provided? Use the z -table.
Convert 68°F to a z-score: z = (68 − 75) / 6 ≈ −1.17. The z-table gives a probability of about 0.1210 to the left of −1.17, which is the percentage of days with highs at or below 68°F. Thus, fewer lifeguards will be provided on about 12.10% of days, choice A.
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