AnswersAlgebra IIMatrices and Sequences

Practice Test Answers

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3

What is the explicit formula for the arithmetic sequence 4 fifths comma 29 over 30 comma 17 over 15 comma 13 tenths ?

A
A sub n is equal to 4 fifths plus 1 sixth times open paren n minus 1 close paren
B
A sub n is equal to 4 fifths plus open paren negative 1 sixth close paren times open paren n minus 1 close paren
C
A sub n is equal to negative 1 sixth plus 4 fifths times open paren n minus 1 close paren
D
A sub n is equal to 1 sixth plus 4 fifths times open paren n minus 1 close paren
4

What is the product? the 2 by 2 matrix, row 1, column 1, 5 column 2, negative 2 row 2, column 1, negative 6 column 2, 2 times the 2 by 1 column matrix row 1 negative 1 row 2 negative 1

A
the 2 by 1 column matrix row 1 negative 7 row 2 8
B
the 2 by 2 matrix, row 1, column 1, 4 column 2, negative 3 row 2, column 1, negative 7 column 2, 1
C
the 2 by 2 matrix, row 1, column 1, negative 5 column 2, 2 row 2, column 1, 6 column 2, negative 2
D
the 2 by 1 column matrix row 1 negative 3 row 2 4
6

Modern Electronics offers a one-year monthly installment plan for a big screen TV. The payment for the first month is 62 dollars , and then it increases by 4 percent each month for the rest of the year. Which expression can be used to find the total amount paid in the first 12 months?

A
62 times open paren the fraction with numerator 1 minus 1 point 0 4 raised to the 0 point 0 4 power and denominator 1 minus 12 close paren
B
62 times open paren the fraction with numerator 1 minus 1 point 0 4 to the 12th power and denominator 1 minus 0 point 0 4 close paren
C
62 times open paren the fraction with numerator 1 minus 1 point 0 4 to the 12th power and denominator 1 minus 1 point 0 4 close paren
D
62 times open paren the fraction with numerator 1 minus 0 point 0 4 to the 12th power and denominator 1 minus 0 point 0 4 close paren
10

Which would be the next step in solving for matrix cap A ? cap A plus the 1 by 4 matrix, row 1, column 1, 3 column 2, negative 4 column 3, negative 11 column 4, 24 is equal to the 1 by 4 matrix, row 1, column 1, 16 column 2, negative 5 column 3, 0 column 4, negative 9

A
cap A is equal to the 1 by 4 matrix, row 1, column 1, 16 column 2, negative 5 column 3, 0 column 4, negative 9 minus the 1 by 4 matrix, row 1, column 1, 3 column 2, negative 4 column 3, negative 11 column 4, 24
B
cap A is equal to the 1 by 4 matrix, row 1, column 1, 16 column 2, negative 5 column 3, 0 column 4, negative 9 plus the 1 by 4 matrix, row 1, column 1, 3 column 2, negative 4 column 3, negative 11 column 4, 24
C
cap A is equal to the 1 by 4 matrix, row 1, column 1, 16 column 2, negative 5 column 3, 0 column 4, negative 9 divided by the 1 by 4 matrix, row 1, column 1, 3 column 2, negative 4 column 3, negative 11 column 4, 24
D
cap A is equal to the 1 by 4 matrix, row 1, column 1, 16 column 2, negative 5 column 3, 0 column 4, negative 9 times the 1 by 4 matrix, row 1, column 1, 3 column 2, negative 4 column 3, negative 11 column 4, 24
12

If cap k is equal to the 3 by 3 matrix, row 1, column 1, negative 2 column 2, 9 column 3, negative 8 row 2, column 1, 7 column 2, 11 column 3, 6 row 3, column 1, 4 column 2, 4 column 3, negative 3 , then what is negative cap k ?

A
the 3 by 3 matrix, row 1, column 1, negative 3 column 2, 8 column 3, negative 9 row 2, column 1, 6 column 2, 10 column 3, 5 row 3, column 1, 3 column 2, 3 column 3, negative 4
B
the 3 by 3 matrix row 1, 2 9 8 row 2, 7 11 6 row 3, 4 4 3
C
the 3 by 3 matrix, row 1, column 1, negative 2 column 2, 9 column 3, negative 8 row 2, column 1, 7 column 2, 11 column 3, 6 row 3, column 1, 4 column 2, 4 column 3, negative 3
D
the 3 by 3 matrix, row 1, column 1, 2 column 2, negative 9 column 3, 8 row 2, column 1, negative 7 column 2, negative 11 column 3, negative 6 row 3, column 1, negative 4 column 2, negative 4 column 3, 3
13

Khalid wrote the given sequence. x minus 1 comma negative 2 x plus 2 comma 4 x minus 4 comma negative 8 x plus 8 comma dot dot dot Which formula can be used to find the 10 th term of the sequence?

A
A sub 10 is equal to open paren x minus 1 close paren times negative 2 raised to the 10 minus 1 power
B
A sub 10 is equal to open paren x minus 1 close paren raised to the 10 minus 1 power
C
A sub 10 is equal to open paren x minus 1 close paren times negative 2 to the 10th power
D
A sub 10 is equal to open paren x minus 1 close paren times 2 raised to the 10 minus 1 power

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