Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divisible by 3. Who is correct, and why?
Answer
A
Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.
B
Sylvia is correct. Any variable term, when it is cubed, always has an exponent divisible by 3.
C
Sylvia is correct. In order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.
D
Miguel is correct. Sylvia confused the perfect square root with the perfect cube root.