Question 9 • Mathematics III
The hypotheses are H₀: μ = $72 and Hₐ: μ < $72. The test statistic is z = (67 − 72)/(11/√40) ≈ −2.88, which is below the 1% lower-tail critical value (about −2.33), so the result is significant. Kavita should reject H₀; the result supports the alternative that the branch’s average receipt is below $72, matching choice B.
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