Question 18 • Mathematics III
The logarithms require x > 0 and x + 7 > 0, so x must be positive. Combining the logs gives log₂[x(x + 7)] = 3, hence x(x + 7) = 2³ = 8. Solving x² + 7x − 8 = 0 gives x = 1 or x = −8, but −8 is outside the domain; the true solution is x = 1, choice A.
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