What is the greatest possible integer value of x for which square root of x minus 5 end root is an imaginary number?
Answer
A
5
B
6
C
3
D
4
Explanation
For √(x − 5) to be imaginary, the number inside the square root must be negative. So x − 5 < 0, which gives x < 5. The greatest integer less than 5 is 4, choice B.
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