Which expression is equivalent to open paren 16 x to the 8th power y to the negative 12 power close paren raised to the 1 half power ?

Raise each factor to the 1/2 power: 16^(1/2) = 4, (x^8)^(1/2) = x^4, and (y^-12)^(1/2) = y^-6. Rewrite y^-6 in the denominator to get 4x^4/y^6, which is choice B.

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